Calculate the length of a chord which is at a distance 6 cm from the centre of a circle of diameter 20 cm.
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Answer:
16cm
Step-by-step explanation:
Diameter of the circle = 20 cm
Radius = 20/2 = 10 cm
OA = 10 cm, OM = 6 cm
Now in right ∆OAM,
OA2 = AM2 + OM2
(By Pythagoras Axiom)
(10)2 = AM2 + (6)2
AM2 = 102 – 62
AM2 = 100 – 36 = 64 = (8)2
AM = 8 cm
OM ⊥ AB
M is the mid-point of AB.
AB = 2 AM = 2 × 8 = 16 cm.
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