Question

calculate the length of a chord which is at a distance of 6cm from the centre of circle of diameter 20cm

Answer 1

let the length of chord be x cm
diameter of circle is 20cm so radius will be 10cm
distance of chord from centre of circle is 6cm
radius of circle act as hypotenuses of triangle ABC (let) and
$\frac{x}{2}$
is the base of triangle ABC which is half the length of chord
according to Pythagoras theorem
${10}^{2} = {6 }^{2} + \frac{x}{2}$
let x/2 be b so
100=36+b2(b square)
64=b2(b square)
b=8
where b=x/2
2b=x
2×8=x
x=16

Answer 2

Here is your answer
Hope it helps you