Question

calculate the length of a second's pendulam at place where acceleration due to gravity is 9.8m/s square​

Answer 1

Answer:

1 m

Explanation:

According to the given question,

T = time period = 2 sec

(As it's a second pendulum)

g = acceleration due to gravity = 9.8 m/s^2

l = length = ?

and we are asked to find the length of the pendulum.

We know,

• T = 2π root (l/g)

Squaring both sides,

• T^2 = (2π)^2 × l/g

Putting the values we get

• 4 = (2π)^2 × l/9.8

• l = 4×9.8/4×π^2

• l = 9.8/(3.14)^2

• l = 9.8/9.8

• l = 1 m

Thus length of the pendulum is 1 m.