Question

Calculate the length of a second's pendulum at a place where g =9.83 m/s^2
Answer it fast ⏩. With explanation ​

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

Calculate the length of a second's pendulum at a place where g =9.83 m/s²

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Time period = 2 sec because it's second's pendulum.
• g = 9.8m/s²

$\large\underline{\underline{\sf To\:Find:}}$

• Lenght of seconds pendulum (l)

We know that -

❏$\large{\boxed{\bf \blue{T=2π\sqrt{\dfrac{l}{g}}} }}$

$\implies{\sf 2=2×π×\dfrac{l}{9.8}}$

On squaring both side

$\implies{\sf (2)^2=\left((2π)^2×\sqrt{\dfrac{l}{9.8}}\right)^2 }$

$\implies{\sf 4=4π^2×\dfrac{l}{9.8} }$

$\implies{\sf l = \dfrac{4×9.8}{4×(3.14)^2} }$

$\implies{\sf l =\dfrac{39.2}{39.4} }$

$\implies{\sf l = 0.99m }$

$\implies{\bf \red{Lenght (l)≈1\:m}}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Length of a second's pendulum is ${\bf \red{1\:m}}$.

Answer 2

Answer:

i thought it was 19.66 becuase i mixed up the signs

Explanation:

i messed up dang