Question

calculate the length of a seconds pendulum at a place where g=9.8 m/s2

Answer 1

Given :
For seconds pendulum T=2secs
g=9.8m/s²

Formula to be used :
T=2π√l/g
⇒ l=gT²/4π²
=9.8x2²/ 4 x (3.14)²
=0.994 m

So  length of simple pendulum is 0.994m

Answer 2

Given : -

For seconds pendulum T = $2$ secs  

g = $9.8 m/s^{2}$

 

Formula to be used : -

T = $2\pi \sqrt\frac{l}{g}$

⇒ l =   $\frac{gt^{2} }{4\pi^{2} }$

⇒ $\frac{9.8X2^{2} }{4X(3.14)^{2} }$

⇒ $0.994$ m

So  length of simple pendulum is $0.994$ m

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