Question

calculate the length of a seconds pendulum on the surface of moon where acceleration due to gravity is 1/6 th the acceleration due to gravity on the earth . ​

Answer 1

Explanation:

The period T of a pendulum at the surface of the Moon is given (approximately) by

T=2πLg−−√T=2πLg

where L is the length of the pendulum and g = 1.62 m/s22 is the acceleration due to gravity on the Moon.

A “seconds pendulum” is one that takes one second to swing each way; thus a “seconds pendulum” on the Moon (or anywhere else) has a period of two seconds. You could use the above formula to calculate the length of a seconds pendulum on the Moon.