Question

calculate the length of an open organ pipe which resonates with a tuning fork of frequency 512 hz.if the velocity of sound in air is 340 m/s ( ignore the end correction)​

Answer 1

length of organ pipe

I= 0.16 m = 16 cm

Explanation:

given data:

Frequency is 512 hz

sound of air is 340 m/s

Frequency of tuning forK can be calculated as

$F = \frac{V}{\lambda}$

for first resonance$I = \frac{\lambda}{4}$

$F = \frac{V}{4I}$

$512 = \frac{340}{4\times I}$

solving for length

I= 0.16 m = 16 cm

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