calculate the length of hypotenuse in the following figure.
Attachments:
Answers
Answered by
1
Answer:2
Step-by-step explanation:
cos 30=adjacent /hyp
sqrt 3/2=sqrt3/x
x=2
Answered by
2
Answer:
here in triangle CBA angle C =30°
and BC = √3
then, cos C =b/h
(cos 30° = √3/2)
√3/2 = √3/AC
AC = 2
Similar questions