Calculate the length of seconds pendulum at a place where acceleration due to gravity is 9.8 and pi=3.14
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Answer:
The answer is "0.994m"
Explanation:
Given data:
The time period for seconds pendulum is "T"=2 seconds
g=9.8m/s²
Formula to calculate length:
T=2π√L/g
L=gT²/4π²
=9.8x2²/ 4 x (3.14)²
=0.994 m
Thus, the length of a seconds pendulum is 0.994m which is approximately equal to 1m. Length "L" = 1m .
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