Question

calculate the length of the chord which is at a distance of 24 cm trom the centre of a circle of radius 26 cm

Answer 1

The answer is 2.Thanks for asking the question

Answer 2

we know that the perpendicular line segment from centre to any chord in circle bisects it therefore,
 
AO = BO
XO = 24cm
XA = XB = 26cm
∠XOA = 90°

AO^2 = AX^2 - OX^2
AO = √676-576 = √100 cm
AO = 10cm

Thus, length of chord is AB= 2*AO = 20cm.