Question

calculate the length of the dna of bacteriophage lambda that has 50000 base pairs

Answer 1

Answer:

Distance between two DNA base pairs: 3.4 Angstorms

As total number of base pairs are 50000,

Total length of DNA =3.4×50000 angstrom

Total length =170,000Angstorms

Answer 2

Base pairs = 50000

$no. \: of \: base \: pairs = \frac{length \: of \: DNA}{0.34 \times {10}^{ - 9} }$

$length \: of \: DNA = 0.34 \times {10}^{ - 9} \times 50000 \\ = 0.34 \times {10}^{ - 9} \times 5 \times {10}^{4} \\ = 1.7 \times {10}^{ - 5} m$