calculate the length of the second pendulum at a place where g=9.8m/s
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Answer:
Time period of pendulum is:
T=2π
g
l
l=
4π
2
T
2
g
l=
4×π
2
4×9.8
l=0.993m=99.3m
l= length of pendulum
g= 9.8m/s
T = Time period of seconds pendulum =2s
I hope it's helpful
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