Calculate the length of wire of radius 0.5 mm needed to prepare a coil of resistance 12 ohms the resistivity of material of the wire is 3.14 into 10 raise to minus 3 m ohms metre
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Given,
Radius of the wire, r= 0.5 mm= 0.5×10⁻³m
Resistance R= 12Ω
Resistivity, ρ= 3.14×10⁻³Ωm
We know that, R=ρ(l/A)
l=RA/ρ
=(12×πr²)/ρ
={12×34.14×(0.5×10⁻³)²}/(3.14×10⁻³)
= 3 m
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