Question

calculate the load placed 10 m from the fulcrum that can be balanced by an effort of 5 N applied at a distance at 4 m from the fulcrum in a lever.

Answer 1

F  

1

​  

=60N,l  

1

​  

=3m,l  

2

​  

=6cm,F  

2

​  

=?

Left hand side moment, about fulcrum

=60×3=180Nm.

Right hand side movement, about fulcrum =6×10  

−2

×xNm.

According to principle of moment,

L.H.M=R.H.M

180=6×10  

−2

×x

x=  

6×10  

−2

 

180

​  

=3000N

Therefore, a force of 3000 N is required to lift the load