Question

Calculate the longest wavelength transition in the pascheneries

Answer 1

apply the equation

wave number = Rh ( 1/ n(1) ^2 – 1/(n2)^2 )

here u mentioned about lyman series and longest wavelength

so, n1 = 1 and n2=2

so, by putting the value

wave number = 109678 ( 1/(1)^2 – 1/(2)^2 )

wave number = 109678 ( 1/1 – 1/4)

= 109678 ( 1-1/4 ) = 109678 * ¾

kindly calculate the above and u will get the answer

HOPE IT CLEARS YOUR DOUBT

CHEERS

Answer 2

Answer:

apply the equation

wave number = Rh ( 1/ n(1) ^2 – 1/(n2)^2 )

here u mentioned about lyman series and longest wavelength

so, n1 = 1 and n2=2

so, by putting the value

wave number = 109678 ( 1/(1)^2 – 1/(2)^2 )

wave number = 109678 ( 1/1 – 1/4)

= 109678 ( 1-1/4 ) = 109678 * ¾

kindly calculate the above and u will get the answer

HOPE IT CLEARS YOUR DOUBT

CHEERS

Explanation: