Calculate the lowest effective resistance that can be obtained by the combination of
three resistors of resistance 4 ohm, 8ohm& 12 ohm
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Answer:
The lowest effective resistance of that can be obtained by the combination of 4Ω, 8Ω & 12Ω resistor is 2.18Ω .
Explanation:
Given:-
R = 4Ω
R" = 8Ω
R"' = 12Ω
We know that when we connect resistors in parallel combination then we get the least value of effective resistance .
Also,
1/Req = 1/R + 1/R" + 1/R"'
= 1/4 + 1/8 + 1/12
= (6 + 3 + 2)/24
= 11/24
Req = 24/11 = 2.18Ω
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