Calculate the lowest possible frequency in the balmer series of spectrum of hydrogen atom?
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Perfect questions for guys interested in maths..
2. The value of x + x(xx) when x = 2 is:
(a) 10, (b) 16, (c) 18, (d) 36, (e) 64
Solution:
x + x(xx)
Put the value of x = 2 in the above expression we get,
2 + 2(22)
= 2 + 2(2 × 2)
= 2 + 2(4)
= 2 + 8
= 10
Answer: (a)
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Answer:
364 is the lowest possible frequency in the balmer series of spectrum of hydrogen atom.
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