Question

Calculate the M.I. of a thin uniform ring about an axis tangent to the ring and in a plane of the ring, if its M.I. about an axis passing through the centre and perpendicular to plane is 5 kg m².​

Answer 1

$\bf \: \frac{ I _{T} }{ I_{e} } = \frac{ \frac{3}{2}mr^{2} }{ {mr}^{2} } = \frac{3}{2} \\ \\ \bf \: I_{T} \: = \frac{3}{2} I_{c} \: = \frac{3}{2} \times 4 = 6$

$\bf \: therefore \: \\ \bf ans : \: = \: 6Kgm²$