Calculate the M.I. of thin uniform rod of mass 100g and length 50 cm about an axis perpendicular to its length and passing through
1. its centre and
2. One end
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Answer:
formula : its centre : ml^2 / 12 = 0.1*(0.5)^2 / 12 = 0.00208333333. its end : ml^2 / 3 = 0.1 *(0.5)^2 / 3 = 0.00833333333.
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