Question

Calculate the magnetic field at a distance of 5 cm from an infinite straight conductor carrying current of 10 A.

Answer 1

$\rm{ \blue{\bigstar Find \longrightarrow }}$

• Magnetic Field-?

$\rm{ \green{\bigstar Given \longrightarrow }}$

• Current = 10A
• Distance = 5cm

$\rm{ \pink{\bigstar Formula \ used \longrightarrow }}$

$\boxed{\bf{ B= \dfrac{\mu_o I}{2\pi d} } }$

where,

B= magnetic field,

I= current

d= Magnetic field at a distance away from the wire.

$\rm{ \orange{\bigstar SoLution \longrightarrow }}$

Firstly we will convert distance 5cm to m,

$\sf{1cm= 0.01 m \implies 5cm= 0.05 m}$

d= 0.05m

Put the value in the formula

$\sf{ B= \dfrac{\mu_o I}{2\pi d} }$

we get,

$\sf{ B= \dfrac{10^{-7}\times 4\pi \times 10}{2 \pi \times 0.05}}$

$\sf{B= \dfrac{10^{-7} \times 2 \times 10 }{0.05} }$

$\boxed{\bf{B= 4\times 10^{-5} T}}$

$\red{\rm{\underline{\therefore Magnetic \ Field \ is \ 4\times 10^{-5} T }}}$

_____________________________

Answer 2

Given ,

Current (I) = 10 A

Distance (r) = 5 cm or 5 × 10^(-2) m

We know that , the magnetic field due to an infinitely long straight conductor is given by

$\boxed{ \tt{B = \frac{ u_{o}I }{2\pi r}}}$

Thus ,

$\tt \implies B = \frac{4\pi \times {(10)}^{ - 7} \times 10}{2\pi \times 5 \times {(10)}^{ - 2} }$

$\tt \implies B = 4\times {(10)}^{ - 5} \: \: testla$

Therefore , the magnetic field is 4 × 10^(-5) T