calculate the magnetic field at the centre of square wire of side root2 and carrying a current of 10 A. plz solve this by formula.
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Please refer to the question: http://brainly.in/question/176834 for the derivation of the formula.
Let us take one side AB of wire whose length is L. Let O be its center. Let P be the center of the square. OP = 1/2 L. The angle APO = angle α = π/4.
The angle BPO = π/4.
Magnetic field at P = B = [ μ₀ I / 4 π (L/2) ] * [ Sin APO + Sin BPO ]
B = [ μ₀ I / 2π L ] [ 1/√2 + 1/√2 ]
= μ₀ * 10 * √2 / (2 π √2)
= 5 μ₀ /π Tesla
Magnetic field due to all the four sides is additive at the center of the square.
B = 20 μ₀ / π Tesla.
Let us take one side AB of wire whose length is L. Let O be its center. Let P be the center of the square. OP = 1/2 L. The angle APO = angle α = π/4.
The angle BPO = π/4.
Magnetic field at P = B = [ μ₀ I / 4 π (L/2) ] * [ Sin APO + Sin BPO ]
B = [ μ₀ I / 2π L ] [ 1/√2 + 1/√2 ]
= μ₀ * 10 * √2 / (2 π √2)
= 5 μ₀ /π Tesla
Magnetic field due to all the four sides is additive at the center of the square.
B = 20 μ₀ / π Tesla.
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refer to http://brainly.in/question/176834 also.
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