Question

calculate the magnetic field strength at the centre of a flat circular coil having 500 turns of radius 50 cm each and carrying a current of 2A.​

Answer 1

Answer:

Magnetic field at center due to one ring is B.

Hence, due to n ring is B,

B=nB

1

where n=500turns.

B

1

=

2r

μ

0

I

where I=current through ring, r=radius of ring.

B=500×

2×π×10

−2

4π×10

−7

×5

=5×10

−2

=0.05T