Calculate the magnetic field when an electron having momentum of 9-1 * 102 kg m s
has a circular radius of path of 0-3 m.
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Explanation:
The radius of the helical path of the electron in the uniform magnetic field is
r=eBmv⊥=eBmvsinθ=(1.6×10−19C)×(0.15T)(2.4×10−23kgms−1)×sin30o
=5×10−4m=0.5×10−3m=0.5mm
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