Question

calculate the magnetic induction at the centre of a coil of radius 20cm when a current of 40mA flow through through 120 turn of coil​

Answer 1

Answer: 1.49 x10^-5

or 1.5× 10^-5

Answer 2

The magnetic induction at the center of the coil is $6.28 * 10^-5 T$.

The magnetic induction at the center of a coil can be calculated using the formula:

B = μnI / R

where:

B is the magnetic induction (in tesla)

μ is the permeability of free space (4 * π * 10^-7 Tm/A)

n is the number of turns in the coil

I is the current flowing through the coil (in Amperes)

R is the radius of the coil (in meters)

In the given problem,

n = 120,

I = 40 mA = $40 * 10^-3 A,$

and R = 20 cm = 0.2 m.

Plugging these values into the formula,

we get:

B = μ nI / 2R

= ($4 * \pi* 10^-7) * 120 * 40 * 10^-3 / (2 * 0.2)$

= $6.28 * 10^-5 T$

So the magnetic induction at the center of the coil is 6.28 * 10^-5 T.

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