Question

calculate the magnetic moment of a divalent cation of atomic number 27​

Answer 1

=3.87 BM .!!!!!!!!!!!!!!!

Answer 2

Answer:

Explanation:

atomic no. 27

configuration is 4s² 3d⁷

2+ cation= 3d⁷

will have 3 unpaired electrons

equation for magnetic moment=$\sqrt{n(n+2)}$ BM

=$\sqrt{3(3+2)}$

=$\sqrt{15}$

=3.8 BM