Question

Calculate the magnetic moment of Mn in Mno2.

Answer 1

Answer:

Oxidation state of Mn in MnO2 is +4, so no. of unpaired electrons in valence shell is 3 (4s⁰ 3d³)

Magnetic moment =

$\sqrt{n( n + 2)}$

Where n is the no. of unpaired electrons

So, Magnetic moment of Mn+4

$\sqrt{3(3 + 2)} =$

$\sqrt{15}$

= 3.872 BM

hope this will help you