Physics, asked by shivakanthmadhu71, 4 months ago

Calculate the magnification if an object of height 3 cm kept in front of a concave
mirror gives a real image of size 6 cm.

Answers

Answered by BrainlyTwinklingstar
28

Given :

In concave mirror,

Height of the object = 3 cm

Height of the image = 6 cm

To Find :

The magnification of the image.

Solution :

using magnification formula that is,

» The Magnification produced by a mirror is equal to the ratio of the height of the image to the height of the object .i.e.,

\boxed{ \bf m = \dfrac{h'}{h} }

where,

  • h' denotes height of the image
  • h denotes height of the object

by, substituting all the given values in the formula,

\dashrightarrow \sf m =  \dfrac{h'}{h}

\dashrightarrow \sf m =  \dfrac{6}{3}

\dashrightarrow \sf m =  2

The magnificence of the image is 2.

Here we can see the image is enlongated that is the image is bigger than object.

Answered by MathTeacher029
2

Given :

In concave mirror,

Height of the object = 3 cm

Height of the image = 6 cm

To Find :

The magnification of the image.

Solution :

using magnification formula that is,

» The Magnification produced by a mirror is equal to the ratio of the height of the image to the height of the object .i.e.,

\boxed{ \bf m = \dfrac{h'}{h} }m=hh′

where,

h' denotes height of the image

h denotes height of the object

by, substituting all the given values in the formula,

The magnificence of the image is 2.

Here we can see the image is enlongated that is the image is bigger than object.

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