Calculate the magnification of the image of an object placed perpendicular to the principal axis of a concave mirror of focal length 15 cm. The object is at a distance of 20 cm from the mirror.
Answers
Answer:
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Answer:
The image magnification produced is -2.
Explanation:
For a spherically curved mirror in air, the magnitude of the focal length is equal to the radius of curvature of the mirror divided by two. The focal length is positive for a concave mirror.
Therefore, the focal length of the mirror is 20 cm / 2 = 10 cm.
The mirror equation expresses the quantitative relationship between the object distance (do), the image distance (di), and the focal length (f). The equation is stated as follows:
1/f 1/do+ 1/di
So, 1/di= 1/f- 1/do = 1/10 - 1/15
Therefore, di = 30 cm.
The magnification equation relates the ratio of the image distance and object distance to the ratio of the image height (hi) and object height (ho). The magnification equation is stated as follows:
M = hi/ho= -(di / do) = -(30/15) = -2.
Hence,
the image magnification produced is -2.
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