Question

Calculate the magnitude and direction of electric field which keeps a proton just floating. given that mass of the proton is 1.67*10^-27 kg and charge on proton is 1.6*10^-19 and is 9.8

Answer 1

Electric field = 1 × 10⁻⁷ N/C.

Explanation:

Mass of proton m = 1.67 * 10^-27 kg

The electric force acting on proton, Fe = qE

Where q is the change and E is the electric field.

We know that the force acting on it to balance electrostatic force will be its weight mg. Hence mg = qE

So E = mg / q

Taking g = 10  m/s2

Substituting, we get:

 E = 1.67 * 10^-27 * 10 / (1.6 * 10^-19)

    = 1 * 10^-7

The electric field that balances the mass of proton is 1 × 10⁻⁷ N/C.

Answer 2

Answer:

hope it will be helpful.