Question

calculate the magnitude field inside the solenoid when the length of the solenoid become twice fixed number of turns?​

Answer 1

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A solenoid is a type of electro magnet which is made of a soft iron core and a current carrying conductor.

Magnetic field of solenoid is directly proportional to number of turns around the soft iron core. If the number of turns of conductor or wire is increased them the magnetic field will also increases. When number of turns will decrease then the magnetic field will also decrease.

But, the magnetic field of a solenoid is inversely proportional to length of core or solenoid. If the length of solenoid is increased then magnetic field will decrease, if the length of solenoid is decreased then the magnetic field will decrease.

Now if length of solenoid becomes twice fixed number of turns then magnetic field of solenoid will decrease.

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Answer 2

Solution ;

We know that Magnetic field inside the solenoid is :

$\pink{\bf\:B=u_{o}\:n\:I}$

where ,

• n = N/L , i.e total no if turns per unit length
• I = Current

We have to find the magnitude field inside the solenoid when the length of the solenoid become twice and number of turns are fixed .

It means Length , L'=2L

and N is fixed

so ,$\sf\:B=u_{o}\dfrac{N}{L'}\:I$

$\sf\:B=u_{o}\dfrac{N}{2L}\:l$

$\sf\:B=\dfrac{1}{2}\:u_{o}\:N\:l$

$\sf\:B=\dfrac{1}{2}B_{o}$

Hence, magnitude field inside the solenoid will decrease half of the initial value ,when the length of the becomes double and no of turn are fixed .