Physics, asked by rajandhanya93, 10 months ago

Calculate the magnitude of charge if the force between them is 90 N and they are at a distance 5 cm apart.

Answers

Answered by Anonymous

Answer:

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d represents the distance of separation between the two objects (in meters). The symbol k is a proportionality constant known as the Coulomb's law constant. The value of this constant is dependent upon the medium that the charged objects are immersed in. In the case of air,

the value is approximately 9.0 x 10^ 9 N • m^2 / C^2.

<Coulomb's Law>

Here Q1 = Q2 = Q

d= 5 cm = 5 .10^-2 m

F = 0.144 N

therefore F = (k. Q^2) / d^2 or Q = sqrt{ (F.d^2) /k}

substituting the values

The charge Q = Sqrt {{0.144 N . 25.10^-4 m^2}/ {9. 10^9 N.m^2 /C^2} }

Q=0.2 10^-6 C =0.2 micro coulomb

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Answered by Vishal101100

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F = Kq1q2/r²

90 N = 9×10^-9 q1q2/(5×10-²)²

90/9×10^-9 = q1q2/(5×10-²)²

10^10 × 25×10^-4 = q1q2

2.5×10^7 = q1q2

q1 = 2.5×10^7/q2

and q2 = 2.5×10^7/q1

hope it helps.

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