calculate the magnitude of induced emf in a coil of inductance 1mH in which current is changing from 0.1A To 2.1A in 0.01sec
Answers
Answered by
6
Answer: -0.2 volts
Explanation: Induced emf = -Ldi/dt
=-1mH x (2.1-0.1)/0
01=-0.2 volts
Answered by
1
Given,
Inductance=1mH
Current changing from 0.1A to 2.1A
Time=0.01sec
To Find,
Magnitude of induced emf.
Solution,
We have the formula to calculate magnitude of induced emf,
e=-L(di/dt)
=-1mH(2.1-0.1A/0.01sec)
=-1mH(2/0.01)
=-10^-3H×200
=-0.2Volts
Hence, magnitude of induced emf in a coil is 0.2volts.
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