Question

calculate the magnitude of resultant of two unit vectors making an angle 60° with each other?​

Answer 1

Answer:

Explanation:

Set a=(2,0) and b=(2*cos(60^0),2*sin(60^0) so

a-b = (2–2*cos(60^0),0–2*sin(60^0)) = (2–1,-2*sqrt(3)/2) = (1,-sqrt(3))

||a-b|| = sqrt((a-b)^2) = sqrt(1^2+3) = 2

Answer 2

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