calculate the magnitude of the current I3 in the following circuit.
a 7a
b 13a
c -13a
d 7a
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I think the answer is -7A
as l1 has 3 A and l2 has 10 A
by the junction law 3A = 10 A + current in l3
3 = 10 + current in l3
-7 = current in l3
as l1 has 3 A and l2 has 10 A
by the junction law 3A = 10 A + current in l3
3 = 10 + current in l3
-7 = current in l3
nonamebutfame:
sir solv it
which way u solve it
is it ok now?
reply please?
thanks sir
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