Question

Calculate the magnitude of the electric field at a point 4 centimetre away from a line charge density 2 x 10 to the power minus 6 coulomb per metre

Answer 1

Answer:.

Explanation:.

Answer 2

$\huge\mathfrak\red{Solution}$

We know, Electric Field Intensity = λ/2πε₀r

Given ⇒

Linear charge Density (λ) = 2 × 10⁻⁶ C/m.

Distance(r) = 4 cm.

= 0.04 m.

Also, ε₀ = 8.85 × 10⁻¹²

Now, Using the Formula,

Electric Field Intensity(E) = λ/2πε₀r

∴ E = (2 × 10⁻⁶) ÷ (2 × 22/7 × 8.85 × 10⁻¹² × 0.04)

⇒ E = 10⁶/1.1126

∴ E = 0.899 × 10⁶

∴ E = 8.99 × 10⁶ N/C.

Hence, the Electric Field Intensity is 8.99 × 10⁶ N/C.