Question

Calculate the magnitude of the force , due to an electric dipole of Dipole moment 3.6 * 10 rest to the power -6 Coulomb meter , on an electron 25 nm from the centre of the dipole , along the dipole axis . Assume that this distance is large relative to the dipole's Charge seperation.

Answer 1

Given that,

Dipole moment of the electric dipole, $p=3.6\times 10^{-6}\ C-m$

Distance from the center of dipole, $r=25\ nm=25\times 10^{-9}\ m$

To find,

The magnitude of the force due to an electric dipole

Solution,

The electric force is given by :

$F=qE$

E is electric field due to electric dipole

$F=\dfrac{2pq}{4\pi \epsilon_o r^3}\\\\F=\dfrac{2pqk}{r^3}\\\\F=\dfrac{2\times 3.6\times 10^{-6}\times 1.6\times 10^{-19}\times 9\times 10^9}{(25\times 10^{-9})^3}\\\\F=6.63\times 10^8\ N$

So, the electric force on the electric dipole is $6.63\times 10^8\ N$.

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Electric dipole

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