Question

calculate the male fraction of asota Benzene a ccl4 present in a solution which consists 2 mol of Benzene (c6H6) and 3moles of ccl4 are 5moles of acetone ​

Answer 1

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Answer

Let the mass of solution be 100 gm

Mass of Benzene =30 gm

Mass of CCl4=70 gm

Moles of Benzene =7830=0.385

Moles of CCl4=15470=0.45 moles

Mole fraction (Benzene) =0.385+0.450.385=0.461

Answer 2

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