Question

calculate the mass and number of molecules and number of each constituent atoms in 3.4 gram of ammonia gas​

Answer 1

R.M.M of Ammonia (NH3) is 14 + 3*1 =>17 g mol-1

Hence, 3.4 g of NH3 is 3.4/17 mol =>0.2 mol .

1 mol of gas contains 6.023 * 10^23 molecules.

So, 0.2 mol is 0.2*6.023*10^23 molecules of NH3.

1.2046*10^23 molecules of NH3.

As each molecule of NH3 contains 1 atom of N and 3 atoms of H.

1.2046*10^23 atoms of N.

3*1.2046*10^23 atoms of H.

3.6138*10^23 atoms of H.