Question

Calculate the mass and volume and mass of 0.2 mole of O3 at STP​

Answer 1

Explanation:

$\bold{(a) \: \sf{For \: Calculation \: of \: mass}} \\ \sf{Mass \: of \: 1 \: mole \: of \: O_{3} = 48g} \\ \sf{Mass \: of \: 0.2 \: mole \: of \: O_{3} = 48 \times 0.2gm} \\ \boxed{ \sf{Mass \: of \: 0.2 \: mole \: of \: O_{3} = 9.6g}} \\ \\ \bold{(b) \: \sf{For \: Calculation \: of \: volume}} \\ \sf{Volume \: of \: 1 \: mole \: of \: O_{3} \: at \: STP = 22.4L} \\ \sf{Volume \: of \: 0.2 \: mole \: of \: O_{3} \: at \: STP = 22.4 \times 0.2} \\ \boxed{\sf{Volume \: of \: 0.2 \: mole \: of \: O_{3} \: at \: STP = 4.48 \: litre}}$[/tex]

Answer 2

solution

we know that ,

mass of 1 mole of O3 = 48 g

therefore ;

so mass of 0.2 mole of O3 = 0.2× 48 = 9.6 g

volume of 1 mole = 22.4 lite

volume of 0.2 mole = 22.4 × 0.2 = 4.48 l

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