Question

Calculate the mass and volume of o2 required at stp to convert 2.4kg of graphite in to co2

Answer 1

Answer:

The chemical equation for the process is:

C+O2 →CO2

For the above reaction, 1 mole of O2 will burn 1 mole of C completely.

In 2.4 g C, number of moles =2.4/12=0.2 moles of oxygen is required.

Volume occupied by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4L.

Therefore, 0.2 mol O2 =0.2×22.4=4.48L.

Explanation:

The chemical equation for the process is:

C+O2 →CO2

For the above reaction, 1 mole of O2 will burn 1 mole of C completely.

In 2.4 g C, number of moles =2.4/12=0.2 moles of oxygen is required.

Volume occupied by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4L.

Therefore, 0.2 mol O2 =0.2×22.4=4.48L.

Answer 2

Explanation:

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