Question

Calculate the mass and volume of oxygen required at STP to convert 9.6kg of charcoal into Carbon dioxide

Answer 1

$\mathfrak{ANSWER}$

C + O2 —> CO2

According to balanced equation,

12 g of Carbon reacts with 32g of oxygen

9.6 kg of Carbon reacts with x g of O2

9.6 kg = 9600g

x = 9600*32/12

x = 25600g of O2

Therefore,25600g of O2 is used for 9.6kg of charcoal

32g of O2 = 1 mole

25600g of O2 = 25600*1/32

=> 800 moles of O2

I mole of O2 at STP = 22.4 litres

800 miles of O2 at STP = 800*22.4

= 17920.0

=[tex]\boxed{17920L}

Therefore, for 9.6kg of charcoal we need ,25600g of O2 or 17920 litres of O2 to convert into carbon dioxide

{Values have been taken in grams }

Answer 2

Answer:

Explanation:

Attachment.....