Question

Calculate the mass and volume of oxygen required at stp to convert 3.6 kg of carbon into carbondioxide

Answer 1

the balance equation of given reaction:
C + O2-CO2
we have 3.6kg C =3600g
now no. of mole of C=3600/12=300n(mole)
In the above equation 1 n of Carbon react with 1n of O2 to give 1 n of CO2
By applying sterechiometry 300 n of Carbon reacts with 300n of O2 to give 300 n of CO2
Now of O2=n×M=300×32=9600g=9.6kg
volume of O2 at STP=n×22.7=300×22.7=6,810L

Answer 2

Answer:

the balance equation of given reaction:

C + O2-CO2

we have 3.6kg C =3600g

now no. of mole of C=3600/12=300n(mole)

In the above equation 1 n of Carbon react with 1n of O2 to give 1 n of CO2

By applying sterechiometry 300 n of Carbon reacts with 300n of O2 to give 300 n of CO2

Now of O2=n×M=300×32=9600g=9.6kg

volume of O2 at STP=n×22.7=300×22.7=6,810L