Question

calculate the mass and volume of oxygen required at stp to convert 2.4 kg of graphite into co2

Answer 1

c+o2——>co2
moles of graphite=w/M
=12/2.4*10^3
=0.5*10^-2
1 moles required 1 mole
0.5*10^-2 required 0.5*10^-2
now, weight of o2=M*n
=32*0.5*10^-2
=0.16g
and volume at stp=22.4L

Answer 2

C + O2( Balanced Equation)

1 mole of graphite reacts with 1 mole of Oxygen to form 1 mole of Co2

Therefore, 12g of graphite reacts 32 g

of oxygen to produce 44g of Co2

The amount of oxygen required to convert 2.4 kg of graphite into Co2

=32/12*2400

=6400g

=6.4 kg

Thank You