Question

Calculate the mass and volume of oxygen required at STP to convert 2.4 kg of graphite into carbon dioxide? answer me fast

Answer 1

The equation for the above reaction is as follows:
(graphite is an allotrope of carbon--C)
       C         +       O2 ------->  CO2         (s)                  (g)                (g)
Therefore 1 mole of graphite requires 1 Mole of O2 to give 1 mole of CO2
Calculate the moles of graphite:
molar mass of C = 12mass = 2400 g 
moles = mass/molar mass           = 2400/12           =200 moles
if 1 mole of C requires 1 mole of O2then 200 moles requires  = 1 x 200 / 1                                         = 200 moles              Find mass of oxygen: (molar mass of O2= 32, moles=200)mass = moles x molar mass         = 200 x 32         = 6400g          = 6.4kg of oxygenFind the volume of oxygen:
Ideal gas law..... states that 1 mole of an ideal gas occupies 22.4 litres.                                            therefore 200 moles of O2 occupies= (22.4 x 200) liters                                                                                  =4480 liters                 volume of oxygen = 4480 liters

Answer 2

Explanation:

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