Question

Calculate the mass and volume of oxygen required at STP to 10kg of graphite into carbon dioxide C + O2 –-----> co2 C=12U, O=16U
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Answer 1

Answer:

2.016 L

Explanation:

CaCO

3

⇌CaO+CO

2

One mole of calcium carbonate on decomposition gives one mole of carbon dioxide.

The molecular weight of calcium carbonate is 100 g/mol.

10 g calcium carbonate corresponds to 0.1 mol. It on decomposition will give 0.1 mol of carbon dioxide. But limestone is only 90% pure. Hence, 0.09 mol of carbon dioxide will be obtained.

1 mole of carbon dioxide occupies 22.4 L at STP.

Hence, 0.09 mol of carbon dioxide will occupy 0.09×22.4=2.016 L.