Chemistry, asked by jiknjkkk, 21 days ago

calculate the mass and volume of oxygen required at stp to convert 5kg of graphite into carbon dioxide​

Answers

Answered by khandelwallipi
1

Explanation:

The volume of oxygen at STP required to convert 5kg of graphite completely is:

The chemical equation for the process is:

C + O2 → CO2

For the above reaction, 1 mole of O2 will burn 1 mole of C completely.

In 5kg C,

number \: of \: graphite \:=\frac{5 \times  {10}^{3} }{12}  </p><p>=\frac{5000}{12}  </p><p>= 416moles \\ for \: 200moles \: of \: graphite \: we \: need </p><p>\: 200mole \:of \: oxygen \\ at \: stp \: 1mole \: o2 \: occupied \: 22.4l \: volume \\ then \: 416mole \: will \: ocupid \: volume</p><p>=  416 \times 22.4 = 9318</p><p>(in \: round \: figure) </p><p>\\ mass \: of \: oxygen \:  =  \\ 1mole = 32gm \\ then \:</p><p> 416 mole \:  = 32 \times 416 </p><p>= 13312gm \: or \: 13.31kg

Volume occupied by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4 l

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