Chemistry, asked by mishka330, 11 months ago

calculate the mass % caco3 in the 103 g mixture containing caco3 and na2co3

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Answered by AshokKumarPanda
7

Answer:(2)48.5%

Explanation:If we add actual mass of both compounds tnen we got 206g but we have 103 g

Then it means we have 0.5 mole of each.

In 0.5 mole,mass of caco3= 50g

Mass% of caco3= Mass of caco3/ total mass ×100% =50/103×100%

By solving we get

48.5% ( approx)

Answered by akshita4595
0

Answer:

The answer is B) 48.5%. This is calculated by finding the molar mass of CaCO₃ (100.08 g/mol) and Na₂CO₃ (106.00 g/mol).

Given:

The mass of the mixture of calcium carbonate and sodium carbonate is 103g.

To find:

The mass percentage of CaCO₃ in a 103g mixture of Na₂CO₃.

Solution:

The total molar mass of the mixture is 206.08 g/mol. The mass of CaCO₃ in the mixture is then calculated by multiplying the molar mass of CaCO₃ by the moles of CaCO₃ produced from the reaction, divided by the total molar mass of the mixture. The moles of CaCO₃ produced from the reaction can be calculated using the ideal gas law and the data are given.

The moles of CaCO₃ produced from the reaction are calculated as follows:

n = PV/RT

n = (24 L * 1atm)/(0.0821 L*atm/K*mol * 300K) = 0.087 mol

The mass of CaCO₃ in the mixture is then calculated by multiplying the molar mass of CaCO₃ by the moles of CaCO₃ produced from the reaction, divided by the total molar mass of the mixture:

Mass of CaCO₃ in the mixture = (100.08 g/mol * 0.087 mol)/206.08 g/mol        = 0.049 g

The mass percentage of CaCO₃ in the mixture is then calculated by dividing the mass of CaCO₃ in the mixture by the total mass of the mixture, multiplied by 100:

Mass percentage of CaCO₃ in the mixture = (0.049 g/103 g) * 100 = 48.5%

Therefore, the percentage mass of CaCO₃ is 48.5%.

To know more about mass, click here:

https://brainly.in/question/790970

To learn more about mass percentage, click below:

https://brainly.in/question/24962876

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