Question

Calculate the mass defect, binding energy and binding energy per nuclear og 5b10 nucleus. given mass of proton =1•00759 amu, mass of nutron = 1•00898 amu and mass of 5b10=10.01294 amu.

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Answer 1

Answer:

Given,

Mass of one proton = 1.007825 a.m.u

Mass of one neutron= 1.008665 a.m.u

Nuclear mass of 6 C 12 = 12 a.m.u

(i) 6 C 12 has 6 proton, 6 electron and 6 neutron.

Mass of nucleus = Mass of 6 proton + Mass of 6 neutron

=(6×1.007825)+(6×1.008665)

=12.09894u

Mass defect (Δm) =12.09849u−12u=0.098931u

(ii) Binding Energy = Mass Defect × 931.5MeV

=0.09849u×931.5MeV/u=92.15MeV

(iii) Binding Energy per Nucleon= Binding Energy / Number of Nucleons

Number of nucleon = Mass Number = 12

So, Binding Energy per nucleon = 92.15/12

=7.68MeV

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