Question

calculate the mass % Fe in Mohr salt and % Al and K in potash alum ​

Answer 1

Answer:

=>

molecule mass of

(NH₄)₂Fe(SO₄)₂·6H₂O - 392.1 g/mol

molar mass of Fe - 55.8 g/mol

percentage of Fe in (NH₄)₂Fe(SO₄)₂·6H₂O is,

$= \frac{55.8}{392.1} \times 100 \\ = 14.2 \: percent \:$

so, 14.2 % of Al is present in (NH₄)₂Fe(SO₄)₂·6H₂O.

=>

molecuar mass of KAl(SO₄)₂ - 258.1 g/mol

molar mass of Al - 27 g/mol

percentage of Al in KAl(SO₄)₂ is,

$= \frac{27}{258.1} \times 100 \\ = 10.4 \: percent \:$

So, 10.4 % of Al is present in KAl(SO₄)₂ .