Calculate the mass in gm of 44.8 lit of H2 gas present at S.T.P
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Answer:
since H2 consist of two atoms means 1 mole of H2 contains 2 mole atom of hydrogen . Thus, we can say since 1 mole of H2 or 2 mole atoms of hydrogen occupies = 22.4 litres at N.T.P. So, 2 moles of H atom at NTP occupy a volume of 22.4 L.
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4 gram of hydrogen is present in 44.8 litre of hydrogen gas at standard temperature and pressure.
Explanation:
- This is in accordance to the avogadro's law which states that equal volumes of gases under equal temperature and pressure contains the equal number of molecules. as a result of this 22.4 litre of hydrogen gas contains two moles of hydrogen gas
- hydrogen is a diatomic molecule , one molecule of hydrogen is equal to 2 grams which is present in 22.4 litre. As a result of this in 44.8 litres there is 4 gram of hydrogen gas present. ,
To know more about avogadro's law
State and explain Avogadro's law - Brainly.in
https://brainly.in/question/1782272
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